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click this link here now Problem Statement:
Identify ODD and EVEN elements in one dimensional array
Solution Approach:
- Retrieve the Array Count from User Input
- Retrieve the Array Elements from User Input
- Iterate the array elements
- If array[i] %2 ==0, the array element is Even , else ODD
- Print the array elements using the above condition
package com.java.planforexams.array;
import java.util.Scanner;
public class OddEvenArrayElements {
public static void main(String[] args) {
// Scanner object for reading User Input
Scanner scan = new Scanner(System.in);
int count;
// Receive the Array Element Count from User
System.out.print("Provide the Array Element Count : ");
// Get the Array Count
count = scan.nextInt();
//Set the Array Size with Count value
int arrayInputFromUser[] = new int[count];
// Receive the Array Elements from User.
System.out.println("Enter the elements:");
// Iterate the array elements
for (int incr=0; incr<count; incr++)
{
arrayInputFromUser[incr] = scan.nextInt();
}
for(int incr = 0 ; incr < count ; incr++)
{
if(arrayInputFromUser[incr] % 2 == 0)
{
System.out.print(" \n Array Element is EVEN::: "+
arrayInputFromUser[incr]);
}
else {
System.out.print(" \n Array Element is ODD::: "+
arrayInputFromUser[incr]);
}
}
}
}
Output:
Provide the Array Element Count : 4
Enter the elements:
12
11
34
33
Array Element is EVEN::: 12
Array Element is ODD::: 11
Array Element is EVEN::: 34
Array Element is ODD::: 33
